Complete lexer implementation
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@@ -10,12 +10,54 @@ import Foundation
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public struct Lexer {
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public let templateString:String
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let regex = NSRegularExpression(pattern: "(\\{\\{.*\\}\\}|\\{%.*%\\}|\\{#.*#\\})", options: nil, error: nil)
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public init(templateString:String) {
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self.templateString = templateString
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}
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func createToken(string:String) -> Token {
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func strip() -> String {
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return string[string.startIndex.successor().successor()..<string.endIndex.predecessor().predecessor()].stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceCharacterSet())
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}
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if string.hasPrefix("{{") {
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return Token.Variable(value: strip())
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} else if string.hasPrefix("{%") {
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return Token.Block(value: strip())
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} else if string.hasPrefix("{#") {
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return Token.Comment(value: strip())
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}
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return Token.Text(value: string)
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}
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public func tokenize() -> [Token] {
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return [Token.Text(value: templateString)]
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// Unfortunately NSRegularExpression doesn't have a split.
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// So here's a really terrible implementation
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var tokens = [Token]()
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let range = NSMakeRange(0, countElements(templateString))
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var lastIndex = 0
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let nsTemplateString = templateString as NSString
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regex.enumerateMatchesInString(templateString, options: nil, range: range) { (result, flags, b) in
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if result.range.location != lastIndex {
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let previousMatch = nsTemplateString.substringWithRange(NSMakeRange(lastIndex, result.range.location))
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tokens.append(self.createToken(previousMatch))
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}
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let match = nsTemplateString.substringWithRange(result.range)
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tokens.append(self.createToken(match))
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lastIndex = result.range.location + result.range.length
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}
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if lastIndex < countElements(templateString) {
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let substring = (templateString as NSString).substringFromIndex(lastIndex)
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tokens.append(Token.Text(value: substring))
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}
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return tokens
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}
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}
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